Teach & case

Help a near-peer reason through the idea — when you explain it, you understand it best — then read the real decision it comes from.

A case · you decide

Vela and the speed-camera instant

Vela — a student contesting a speed-camera ticket that claims an exact speed "at the instant" of the flash

The idea in play: a limit is the value a function APPROACHES, not its value AT the point.

The ticket says Vela's car was doing 70 km/h "at the instant" the camera flashed. But speed is distance ÷ time — and over an instant, time is zero. Distance ÷ 0? That's undefined. So how can a speed "at an instant" even mean anything?

Vela computes average speed over shorter and shorter windows around the flash: over 2 seconds, 68.4; over 1 second, 69.2; over 0.1 s, 69.9; over 0.01 s, 69.99…

The exact instant itself is still 0 ÷ 0 — genuinely undefined. But the averages don't wander; they home in on a single number. That approached value is what "instantaneous speed" means.

At the exact instant, the formula is 0 ÷ 0. So is the instantaneous speed simply undefined?

Vela's friend graphs a different function with a literal HOLE at x = 2 (undefined there). Does it have a limit as x → 2?

Take a limit yourself in the Calc Lab →

When two ideas meet: 2 cases with two people

A case · you decide

Vela and Nayeli: a slope built from a limit

Vela & Nayeli — a student who thinks in limits, and a friend who wants the slope of a curve at one point

The idea in play: the slope at a point is the limit of secant slopes as the second point closes in.

Nayeli wants the slope of y = x² at x = 3. A slope needs two points, and she only has one.

Vela takes a second point a distance h away. The secant slope is ((3 + h)² − 9) ÷ h, which simplifies to 6 + h.

At h = 1 the secant slope is 7. At h = 0.1 it is 6.1. At h = 0.001 it is 6.001.

What is the slope of y = x² exactly at x = 3?

Open the Calculus Lab →

A case · you decide

Leda and Nayeli: where the slope is zero

Leda & Nayeli — a student maximising an area, and a friend who reads what the slope says

The idea in play: a smooth maximum sits where the rate of change is zero.

Leda has 40 metres of fence for a rectangular garden and wants the largest area.

If one side is x metres, the other is 20 − x, so the area is A = x(20 − x).

Nayeli computes the rate of change: A′ = 20 − 2x. It is positive while the area is still growing and negative once it starts shrinking.

Which rectangle gives the largest area?

Open the Calculus Lab →